2022-09-29-字符串轮转

面试题 01.09.字符串轮转搜索子字符串JS1234var isFlipedString = function(s1, s2) { // 注意此处不能使用！！转boolean,("").indexOf("") = 0 return s1.length == s2.length && (s1 + s1).indexOf(s2) > -var isFlipedString = function(s1, s2) { // 注意此处不能使用！！转boolean,("").indexOf("") = 0 return s1.length == s2.length && (s1 + s1).indexOf(s2) > -1;};TS123function isFlipedString(s1: string, s2: string): boolean { return s1.length == s2.length && (s1 + s1).indexOf(s2) > -function isFlipedString(s1: string, s2: string): b...